3(2x-1)^2+27=3(2x-1)(2x-1)+27

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Solution for 3(2x-1)^2+27=3(2x-1)(2x-1)+27 equation:



3(2x-1)^2+27=3(2x-1)(2x-1)+27
We move all terms to the left:
3(2x-1)^2+27-(3(2x-1)(2x-1)+27)=0
We multiply parentheses ..
-(3(+4x^2-2x-2x+1)+27)+3(2x-1)^2+27=0
We calculate terms in parentheses: -(3(+4x^2-2x-2x+1)+27), so:
3(+4x^2-2x-2x+1)+27
We multiply parentheses
12x^2-6x-6x+3+27
We add all the numbers together, and all the variables
12x^2-12x+30
Back to the equation:
-(12x^2-12x+30)
We get rid of parentheses
-12x^2+12x+3(2x-1)^2-30+27=0
We add all the numbers together, and all the variables
-12x^2+12x+3(2x-1)^2-3=0
We move all terms containing x to the left, all other terms to the right
-12x^2+12x+3(2x-1)^2=3

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